13x^2+2x=1

Solution for 13x^2+2x=1 equation:

13x^2+2x=1

We move all terms to the left:

13x^2+2x-(1)=0

a = 13; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·13·(-1)
Δ = 56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{56}=\sqrt{4*14}=\sqrt{4}*\sqrt{14}=2\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{14}}{2*13}=\frac{-2-2\sqrt{14}}{26}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{14}}{2*13}=\frac{-2+2\sqrt{14}}{26}
$